MP - 2008-02-29 13:53:11 -
In reply to message 1 from MP
I have got this solution only, yet...
...........................................
<?php
require("phpajax/phpajax.php");
class example1 extends phpajax {
function input() {
aread("hidden1");
aread("hidden2");
}
function main() {
$a = & $this->hidden1;
$b = & $this->hidden2;
//---------------------------
aprint('output1', $a.'|'.$b);
ahide("ashow");
}
}
/* Initiliaze php ajax*/
phpajax::init();
?>
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
<head>
<title>Example of how to implement multi-form pages processing in PHP Ajax</title>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<?php phpajax_js("phpajax/");?>
</head>
<body>
<!-- ____From these imputs I will receive data in phpajax____ -->
<input type="hidden" name="hidden1" id="hidden1"><br/>
<input type="hidden" name="hidden2" id="hidden2"><br/>
<!-- __________form1__________ -->
<input type="text" name="input1" id="input1"><br/>
<input type="text" name="input2" id="input2"><br/>
<input type="button" value="click me"
onmousedown="
document.getElementById('hidden1').value=document.getElementById('input1').value;
document.getElementById('hidden2').value=document.getElementById('input2').value;
"
onmouseup="example1()"
>
<br />
<!-- __________form2__________ -->
<input type="text" name="input3" id="input3"><br/>
<input type="text" name="input4" id="input4"><br/>
<input type="button" value="click me"
onmousedown="
document.getElementById('hidden1').value=document.getElementById('input3').value;
document.getElementById('hidden2').value=document.getElementById('input4').value;
"
onmouseup="example1()"
>
<br />
<!-- __________output__________ -->
result = <span id="output1"></span><br/>
</body>
</html>
................................................
Can it do better? I hope that yes :)
Greeting blackmoor...