Omar Abdallah - 2010-11-20 19:24:15 -
In reply to message 1 from sami
There is a property called debug set it to false
it seems that you have set it to be true or because it is set in the example to be true by default so please remove the line or set it to false
example:
$paginator = new AjaxPaginator('1',$recordsPerPage,$query,$conn);
$paginator->debug = false;
Thanks for using the class, please rate if you like it.